Mr Fletcher hired 2 men to dig a well in his compound. They worked for 10 hours on the first day, 8 hours on the second day and finished the job on the third day after working 15 hours. If Mr Fletcher paid each of them $10 per hour of work, calculate the total amount of money they received altogether?
The total number of hours each worker works in the first 2 days is 10+8 = <<10+8=18>>18 hours.
Since they completed the job in three days, each was compensated for 18+15 = <<18+15=33>>33 hours of work.
Mr Fletcher paid each of the workers $10 per hour of work, meaning for 33 hours, each of the workers received 33*$10 = $<<10*33=330>>330
Since they were two workers, the total amount they received all together after each was paid $330 is $330*2 = $<<330*2=660>>660
#### 660