If two piles of toys added together make 120 toys in total, and the larger of the two piles is twice as big as the smaller one, how many toys are in the larger pile?
First, we set up the equation 3x=120, dividing both sides by three to find that x=40
Then we multiply X by 2 to find that 40*2= <<40*2=80>>80
As 80/2=40, and 40+80=<<120=120>>120, we find the sizes of the two piles as the larger pile is twice as big as the smaller pile, confirming that 80 is the answer.
#### 80