An archaeologist discovered three dig sites from different periods in one area. The archaeologist dated the first dig site as 352 years more recent than the second dig site. The third dig site was dated 3700 years older than the first dig site. The fourth dig site was twice as old as the third dig site. The archaeologist studied the fourth dig site’s relics and gave the site a date of 8400 BC. What year did the archaeologist date the second dig site?
The third dig site was dated from the year 8400 / 2 = <<8400/2=4200>>4200 BC.
Thus, the first dig site was dated from the year 4200 - 3700 = <<4200-3700=500>>500 BC.
The second dig site was 352 years older, so it was dated from the year 500 + 352 = <<500+352=852>>852 BC.
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