Jill is going to resod her front yard. The plot of land in front of her house is 200 feet wide by 50 feet. Her house has a sidewalk that is 3 feet wide and 50 feet long. There are also four flower beds: two right in front of the house that are 4 feet deep by 25 feet long, one that is 10 feet by 12 feet, and a fourth that is 7 feet by 8 feet. How many square feet of sod will she need to cover her yard, minus the sidewalk and flower beds?
The area of the whole front yard is 200 feet by 50 feet, or 200 ft * 50 ft = <<200*50=10000>>10,000 sq.ft.
The sidewalk is 3 feet by 50 feet, or 3ft * 50ft = <<3*50=150>>150 sq.ft.
Each of the flower beds right in front of the house is 4 feet by 25 feet, or 4 ft * 25 ft = 100 sq.ft. There are two, so that's 2 * 100 sq.ft. = 200 sq.ft.
The third flower bed is 10 feet by 12 feet, or 10ft * 12ft = <<10*12=120>>120 sq.ft.
The fourth flower bed is 7 feet by 8 feet, or 7ft * 8ft = <<7*8=56>>56 sq.ft.
The total area of the sidewalk and flower beds is 150 sq.ft + 200 sq.ft + 120 sq.ft + 56 sq.ft = <<150+200+120+56=526>>526 sq. ft.
So Jill will need a total of 10,000 sq.ft - 526 sq.ft = <<10000-526=9474>>9,474 sq.ft. of sod.
#### 9474