Cary is an engineer in charge of designing an irrigation system for three farmers. Farmer Bob grows 3 acres of corn, 9 acres of cotton, and 12 acres of beans. Farmer Brenda grows 6 acres of corn, 7 acres of cotton, and 14 acres of beans. Farmer Bernie grows 2 acres of corn and 12 acres of cotton. If corn takes 20 gallons of water an acre, cotton takes 80 gallons of water an acre, and beans take twice as much water as corn, what percentage of the total water used will go to Farmer Bob's farm?
First figure out how much water beans take by multiplying the water use for corn by 2: 20 gallons/acre * 2 = <<20*2=40>>40 gallons/acre
Next, calculate Bob's water use by multiplying each plant's water use per acre by the number of acres he planted, then adding up the total water use for all three crops: 3 * 20 + 9 * 80 + 12 * 40 = <<3*20+9*80+12*40=1260>>1260
Now do the same thing for Brenda: 6 * 20 + 7 * 80 + 14 * 40 = <<6*20+7*80+14*40=1240>>1240
And do the same thing for Bernie: 2 * 20 + 12 * 80 = 1000
Now add up each farmer's water use to find the total water use: 1260 + 1240 + 1000 = <<1260+1240+1000=3500>>3500
Now divide Bob's water use by the total water use and multiply by 100 to find what percentage of the water he used: 1260 / 3500 * 100 = <<1260/3500*100=36>>36%
#### 36