Jason has six fish in his aquarium. He realizes that every day the number of fish doubles. On the third day he takes out one-third of the fish. On the fifth day he takes out one-fourth of the fish. On the seventh day he adds 15 more fish. How many fish in total does he have?
Start by finding how many fish were in the aquarium on the third day 6 * 2 * 2 = <<6*2*2=24>>24.
On day three, Jason took out one-third of the fish 24 / 3 = <<24/3=8>>8.
So at the end of day three, he has 24 - 8 = <<24-8=16>>16 fish.
On day five he has 16 * 2 * 2 = 64 fish, but he takes out one-fourth.
So he took out 64 / 4 = <<64/4=16>>16 fishes.
So at the end of day five, he has 64 - 16 = <<64-16=48>>48 fish.
On day seven he has 48 * 2 * 2 = <<48*2*2=192>>192 fish.
He adds in 15 more, so he has 192 + 15 = <<192+15=207>>207 fish in total.
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