A rival football team has won twice as many matches as the home team they will be playing did. If records show that the home team has won three matches, and each team drew four matches and lost none, how many matches have both teams played in total?
The rival team won twice as many as the home team who won 3 matches so they won 2*3 = <<2*3=6>>6 matches
They both drew 4 matches each for a total of 2*4 = 8 matches
The total number of matches played is 3+6+8 = <<3+6+8=17>>17 matches
#### 17