Zain has 10 more of each coin than Emerie. If Emerie has six quarters, seven dimes, and five nickels, how many coins does Zain have?
If Emerie has six quarters, Zain has 6+10 = <<6+10=16>>16 quarters.
At the same time, Zain has 7+10 = <<7+10=17>>17 dimes, ten more than Emerie.
The total number of quarters and dimes Zain has is 17+16 = <<17+16=33>>33 coins.
Zain also has 10 more nickels than Emerie, a total of 10+5 = <<10+5=15>>15 nickels.
In total, Zain has 33+15 = <<33+15=48>>48 coins.
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