The sum of the ages of three boys is 29. If two of the boys are the same age and the third boy is 11 years old, how old are the other two boys?
The third boy is 11 so the sum of the ages of the first two is 29-11 = <<29-11=18>>18
The ages of the first two boys are equal so each of them is 18/2 = <<18/2=9>>9 years
#### 9