Archer caught eight fish from the lake to sell in the market. When he reached the market, he sold the fish faster than he had anticipated and decided to go back to the lake and catch more fish. He caught 12 more fish in the second round than he had caught earlier. The demand was even greater, and he had to close the day by catching 60% more fish than the number he had caught in the second round and sold all of them in the market. How many fish did he catch that day?
He caught 12 more fish in the second round than he had caught earlier, a total of 12+8=<<12+8=20>>20 fish.
The total number of fish he caught in the two rounds is 20+8=<<20+8=28>>28
In the third round, Archer caught 60/100*20=<<60/100*20=12>>12 fish which were 60% more fish than the number he had caught in the second round.
This means he caught a total of 12+20 = <<12+20=32>>32 fish
Archer caught a total of 28+32=<<28+32=60>>60 fish on that day.
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