有功功率中位数计算排除掉<=0的情况

etl/wind_power/min_sec/StatisticsAndSaveFile.py

@@ -5,7 +5,7 @@ from os import path
 
 import numpy as np
 import pandas as pd
-
+import math
 from etl.common.PathsAndTable import PathsAndTable
 from etl.wind_power.min_sec import TransParam
 from etl.wind_power.min_sec.ClassIdentifier import ClassIdentifier
@@ -109,9 +109,12 @@ class StatisticsAndSaveFile(object):
             df['time_stamp'] = df['time_stamp'].dt.floor('10T')
             df = df.groupby(['wind_turbine_number', 'time_stamp']).mean().reset_index()
 
-        power = df.sample(int(df.shape[0] / 100))['active_power'].median()
+        power_df = df[df['active_power'] > 0]
+        power = power_df.sample(int(power_df.shape[0] / 100))['active_power'].median()
+        del power_df
+        trans_print(wind_col_name, '有功功率，中位数', power)
         if power > 100000:
-            df['active_power'] = df['active_power'] / 100000
+            df['active_power'] = df['active_power'] / 1000
         ## 做数据检测前,羡强行处理有功功率
         # df = df[df['active_power'] < 50000]